⚛️ Fizika · Dinamika · ★★★
Jism qiyalik burchagi 30° bo'lgan qiya tekislikdan sirpanib tushmoqda. Ishqalanish koeffitsienti √3/5 bo'lsa, jismning tezlanishi qancha? (g = 10 m/s²)
- A)3 m/s²
- B)2 m/s²
- C)8 m/s²
- D)5 m/s²
👀 To'g'ri javob va tushuntirishni ko'rish
✓ B) 2 m/s²
💡 a = g(sinα − μcosα) = 10·(0,5 − (√3/5)·(√3/2)) = 10·(0,5 − 0,3) = 2 m/s².