π Matematika Β· Progressiyalar Β· β β β
Cheksiz kamayuvchi geometrik progressiyaning yig'indisi 24 ga, maxraji 1/4 ga teng. Uning birinchi hadini toping.
- A)6
- B)32
- C)18
- D)30
π To'g'ri javob va tushuntirishni ko'rish
β C) 18
π‘ S = bβ/(1 β q) β bβ = 24 Β· 3/4 = 18.